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LinkedIn · Tango

LinkedIn Tango #755 answer — November 1, 2026

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  1. 1A first footholdShow hint
  2. 2Halfway thereShow hint
  3. 3Solve it step by stepShow hint

    Rows count from the top and columns from the left. The rule doing most of the work: no more than two suns or two moons may sit next to each other in a row or column.

    1. Row 1 needs just one more moon, and the × sign between columns 5 and 6 means one of those two cells is a moon. So column 4 of that row is a sun.
    2. Row 1 has two suns side by side in columns 3 and 4, so column 5 of that row is a moon.
    3. Row 1, column 6 is joined by an × sign to the moon to its left, so it is the opposite: a sun.
    4. Row 2, column 6 is joined by an × sign to the sun above it, so it is the opposite: a moon.
    5. Suppose row 5, column 1 were a moon. Then row 6, column 1 would be a moon too, because of the = sign above it. That would give column 1 four moons, and it can only hold three. So row 5, column 1 is a sun.
    6. Row 6, column 1 is joined by an = sign to the sun above it, so it is a sun too.
    7. Row 6, column 2 is joined by an × sign to the sun to its left, so it is the opposite: a moon.
    8. Column 1 has two suns one above the other in rows 5 and 6, so row 4 of that column is a moon.
    9. Suppose row 2, column 2 were a moon. Then row 2 would have two moons side by side in columns 1 and 2, so column 3 of that row would be a sun. Then row 2 would have its three moons, so columns 4 and 5 of that row would be suns. That would make three suns in a row, in columns 3, 4, and 5 of row 2. So row 2, column 2 is a sun.
    10. Suppose row 2, column 5 were a moon. Then row 2 would have two moons side by side in columns 5 and 6, so column 4 of that row would be a sun. Then row 2 would have suns in columns 2 and 4, so column 3 between them would be a moon. That would give row 2 four moons, and it can only hold three. So row 2, column 5 is a sun.
    11. Suppose row 5, column 2 were a moon. Then column 2 would have two moons one above the other in rows 5 and 6, so row 4 of that column would be a sun. Then column 2 would have suns in rows 2 and 4, so row 3 between them would be a moon. That would give column 2 four moons, and it can only hold three. So row 5, column 2 is a sun.
    12. Row 5 has two suns side by side in columns 1 and 2, so column 3 of that row is a moon.
    13. Suppose row 5, column 6 were a sun. Then row 5 would have its three suns, so columns 4 and 5 of that row would be moons. That would make three moons in a row, in columns 3, 4, and 5 of row 5. So row 5, column 6 is a moon.
    14. Row 4, column 6 is joined by an = sign to the moon below it, so it is a moon too.
    15. Row 6, column 6 is joined by an × sign to the moon above it, so it is the opposite: a sun.
    16. Row 6, column 5 is joined by an × sign to the sun to its right, so it is the opposite: a moon.
    17. Row 6, column 4 is joined by an = sign to the moon to its right, so it is a moon too.
    18. Row 6 has two moons side by side in columns 4 and 5, so column 3 of that row is a sun.
    19. Column 6 has two moons one above the other in rows 4 and 5, so row 3 of that column is a sun.
    20. Suppose row 2, column 3 were a sun. Then column 3 would have two suns one above the other in rows 1 and 2, so row 3 of that column would be a moon. Then column 3 would have moons in rows 3 and 5, so row 4 between them would be a sun. That would give column 3 four suns, and it can only hold three. So row 2, column 3 is a moon.
    21. Row 2 already has its three moons, so its last open cell, column 4, is a sun.
    22. Column 4 has two suns one above the other in rows 1 and 2, so row 3 of that column is a moon.
    23. Suppose row 3, column 3 were a moon. Then row 3 would have two moons side by side in columns 3 and 4, so columns 2 and 5 of that row would be suns. That would give row 3 four suns, and it can only hold three. So row 3, column 3 is a sun.
    24. Row 3 has suns in columns 1 and 3, so column 2 between them is a moon: another sun would make three in a row.
    25. Row 3 already has its three suns, so its last open cell, column 5, is a moon.
    26. Column 2 already has its three moons, so its last open cell, row 4, is a sun.
    27. Column 3 already has its three suns, so its last open cell, row 4, is a moon.
    28. Row 4 already has its three moons, so its open cells, columns 4 and 5, are suns.
    29. Column 4 already has its three suns, so its last open cell, row 5, is a moon.
    30. Row 5 has two moons side by side in columns 3 and 4, so column 5 of that row is a sun.
  4. 4Tango #755 solutionShow answer
    1. Row 1: ☾ ☾ ☀ ☀ ☾ ☀
    2. Row 2: ☾ ☀ ☾ ☀ ☀ ☾
    3. Row 3: ☀ ☾ ☀ ☾ ☾ ☀
    4. Row 4: ☾ ☀ ☾ ☀ ☀ ☾
    5. Row 5: ☀ ☀ ☾ ☾ ☀ ☾
    6. Row 6: ☀ ☾ ☀ ☾ ☾ ☀

    ☀ = sun, ☾ = moon

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How to play Tango

  • Fill every cell with either a sun or a moon.
  • Each row and each column holds the same number of suns and moons — three of each on a 6×6 board.
  • No more than two identical symbols may sit next to each other in a row or column.
  • Cells joined by = must match; cells joined by × must be opposites.

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