LinkedIn Tango #741 answer — October 18, 2026

Rows count from the top and columns from the left. The rule doing most of the work: no more than two suns or two moons may sit next to each other in a row or column.

1. Row 1 has two moons side by side in columns 2 and 3, so column 4 of that row is a sun.
2. Suppose row 6, column 1 were a moon. Then row 6 would have its three moons, so columns 2 and 3 of that row would be suns. That would make three suns in a row, in columns 2, 3, and 4 of row 6. So row 6, column 1 is a sun.
3. Suppose row 2, column 1 were a sun. Then column 1 would have two suns one above the other in rows 1 and 2, so row 3 of that column would be a moon. Then column 1 would have its three suns, so rows 4 and 5 of that column would be moons. That would make three moons in a row, in rows 3, 4, and 5 of column 1. So row 2, column 1 is a moon.
4. Suppose row 2, column 4 were a sun. Then column 4 would have two suns one above the other in rows 1 and 2, so row 3 of that column would be a moon. Then column 4 would have its three suns, so rows 4 and 5 of that column would be moons. That would make three moons in a row, in rows 3, 4, and 5 of column 4. So row 2, column 4 is a moon.
5. Suppose row 5, column 1 were a sun. Then column 1 would have two suns one above the other in rows 5 and 6, so row 4 of that column would be a moon. Then column 1 would have moons in rows 2 and 4, so row 3 between them would be a sun. That would give column 1 four suns, and it can only hold three. So row 5, column 1 is a moon.
6. Suppose row 5, column 4 were a sun. Then column 4 would have two suns one above the other in rows 5 and 6, so row 4 of that column would be a moon. Then column 4 would have moons in rows 2 and 4, so row 3 between them would be a sun. That would give column 4 four suns, and it can only hold three. So row 5, column 4 is a moon.
7. Suppose row 1, column 5 were a moon. Then row 2, column 5 would be a moon too, because of the = sign above it. Then row 3, column 5 would be a sun, because of the × sign above it. Then row 4, column 5 would be a moon, because of the × sign above it. That would give column 5 four moons, and it can only hold three. So row 1, column 5 is a sun.
8. Row 2, column 5 is joined by an = sign to the sun above it, so it is a sun too.
9. Row 3, column 5 is joined by an × sign to the sun above it, so it is the opposite: a moon.
10. Row 4, column 5 is joined by an × sign to the moon above it, so it is the opposite: a sun.
11. Row 1 has two suns side by side in columns 4 and 5, so column 6 of that row is a moon.
12. Column 5 already has its three suns, so its last open cell, row 5, is a moon.
13. Row 5 has two moons side by side in columns 4 and 5, so columns 3 and 6 of that row are suns.
14. Row 5 already has its three moons, so its last open cell, column 2, is a sun.
15. Row 4, column 2 is joined by an × sign to the sun below it, so it is the opposite: a moon.
16. Row 3, column 2 is joined by an × sign to the moon below it, so it is the opposite: a sun.
17. Row 6, column 2 is joined by an × sign to the sun above it, so it is the opposite: a moon.
18. Row 6 already has its three moons, so its last open cell, column 3, is a sun.
19. Column 3 has two suns one above the other in rows 5 and 6, so row 4 of that column is a moon.
20. Row 4 has two moons side by side in columns 2 and 3, so columns 1 and 4 of that row are suns.
21. Row 4 has two suns side by side in columns 4 and 5, so column 6 of that row is a moon.
22. Column 1 already has its three suns, so its last open cell, row 3, is a moon.
23. Column 2 already has its three moons, so its last open cell, row 2, is a sun.
24. Column 4 already has its three suns, so its last open cell, row 3, is a moon.
25. Row 3 has two moons side by side in columns 4 and 5, so columns 3 and 6 of that row are suns.
26. Column 3 already has its three suns, so its last open cell, row 2, is a moon.
27. Row 2 already has its three moons, so its last open cell, column 6, is a sun.